Nootan Isc Physics Class 12 Pdf 281 Extra Quality

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    Nootan Isc Physics Class 12 Pdf 281 Extra Quality



     
     
     
     
     
     
     

    Nootan Isc Physics Class 12 Pdf 281

    In this section we will study the general behaviors of physical systems in a relatively fixed
    atmosphere, i.e. we assume the earth, and therefore the ball, to be at rest in the center of the
    universe. Mass-energy is conserved in all events of this section, therefore, F = m1 + m2 = m1 M = (m1 m2 /
    1/2) – mc2 is conserved in all the physical processes discussed here, and because this is not
    just any electric field that is involved but a physical field, there is a physical consequence
    involved.
    In the limit, all energies are very small, $ \leq \, mc2$
    , and the non-zero particle masses are also very small. This is typical of a very short range
    electrostatic field.
    5 Using this set of equations, calculate the minimum and maximum values of the electric
    field that can be maintained by a charged particle moving in a circular path in an influential
    electrostatic field.
    Solution:
    5
    i.
    ii.
    iii.
    iv.
    v.
    Use the differential equation approach: $ F = \Delta \,\overline{E}$
    where $\Delta$ is the difference between the maximum and the minimum values of the
    field. Therefore, $ \Delta \,\overline{E} = \frac{q \,\Delta \,v}{2 \,\pi \,r} $
    Using the initial assumptions, we have $ \overline{E} \,\,\ll \, mc2 $
    Therefore, $ F = \Delta \,\overline{E} \approx \frac{q \,\Delta \,v}{2 \,\pi \,r} $
    The minimum value of $ \Delta \,v $ is when $ r=R $, the radius of the circle. $ \Delta \,v = R \,\Delta \,\theta $
    The maximum value of $ \Delta \,v $ is when $ r=0 $, the center of the circle. $ \Delta \,v = \Delta \,\theta $
    $ \Delta \,\overline{E} = \frac{q \,\Delta \,v}{2 \,\pi \,r} = \frac{

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