# Nootan Isc Physics Class 12 Pdf 281 Extra Quality

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Nootan Isc Physics Class 12 Pdf 281 Extra Quality

Nootan Isc Physics Class 12 Pdf 281

In this section we will study the general behaviors of physical systems in a relatively ﬁxed
atmosphere, i.e. we assume the earth, and therefore the ball, to be at rest in the center of the
universe. Mass-energy is conserved in all events of this section, therefore, F = m1 + m2 = m1 M = (m1 m2 /
1/2) – mc2 is conserved in all the physical processes discussed here, and because this is not
just any electric field that is involved but a physical field, there is a physical consequence
involved.
In the limit, all energies are very small, $\leq \, mc2$
, and the non-zero particle masses are also very small. This is typical of a very short range
electrostatic field.
5 Using this set of equations, calculate the minimum and maximum values of the electric
field that can be maintained by a charged particle moving in a circular path in an inﬂuential
electrostatic field.
Solution:
5
i.
ii.
iii.
iv.
v.
Use the differential equation approach: $F = \Delta \,\overline{E}$
where $\Delta$ is the difference between the maximum and the minimum values of the
field. Therefore, $\Delta \,\overline{E} = \frac{q \,\Delta \,v}{2 \,\pi \,r}$
Using the initial assumptions, we have $\overline{E} \,\,\ll \, mc2$
Therefore, $F = \Delta \,\overline{E} \approx \frac{q \,\Delta \,v}{2 \,\pi \,r}$
The minimum value of $\Delta \,v$ is when $r=R$, the radius of the circle. $\Delta \,v = R \,\Delta \,\theta$
The maximum value of $\Delta \,v$ is when $r=0$, the center of the circle. $\Delta \,v = \Delta \,\theta$
\$ \Delta \,\overline{E} = \frac{q \,\Delta \,v}{2 \,\pi \,r} = \frac{

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